Must be TrueDiff: Medium

Logic Breakdown

Passage Summary: We have a set of coins where you can't have two people's faces on the same coin, and every coin with a judge on it is guaranteed to have a tree on the back.

Reasoning: The rules established are: 1) No coin has two heads (Judge or Explorer). 2) If a coin has a Judge's head, the other side must be a Tree.

Analysis: This is a formal logic puzzle. From the rules, we know a Judge (J) must be paired with a Tree (T). This means a coin with a Judge cannot have a Building (B) or an Explorer (E) on the other side. Furthermore, using the contrapositive, if a coin does *not* have a Tree on one side, it cannot have a Judge on the other. We can't say much about Explorer coins other than they can't have a Judge or another Explorer on the back. Look for an answer that strictly follows these deductive constraints without making outside assumptions.

Passage Stimulus

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14.

If the statements above are true, which one of the following must be true of the coins in the sample?

Correct Answer
D
D must be true: if a coin shows a judge’s head, the other side must be a tree (J -> T), so a building cannot be on the other side.
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